Question

if a bar is equals to 3 ICAP + 2 J cap + 2 k cap and b bar equals to two ICAP - 2 J cap + 4 k cap the unit vector perpendicular to the plane containing a bar and B were is​

Answer 1

Answer:

(2/√308) (6i - 4j + 5k)

Explanation:

We let that the vector a = 3i + 2j + 2K and the vector b will be= 2i -2j + 4k

Also from the question we get that the product of A & B will have to be  perpendicular. Hence, to find it we have to use the cos product rule and which on solving we will get the value of the new vector as:-

i   j  k

3  2  2

2 -2  4

= i ( 2*4 -(-2)*2)  - j (3*4 -2*2) + k (3*(-2) -(2)*2).

= 12i - 8j + 10k.

So the Magnitude of vector = √(12² + 8² + 10²) = √308.

And the Unit Vector = (1/√308) (12i - 8j + 10k)

= (2/√308) (6i - 4j + 5k).

Answer 2

Explanation:

okay na

the answer