If a bar =mi+2j-3k and b bar=3i-2j+nk are colliner,then(m,n)=
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Answer:
(m, n) = ( – 3 , – 3 )
Step-by-step explanation:
Since a bar and b bar are collinear
Therefore Ai / Bi = Aj / Bj = Ak / Bk
Ai / Bi = m / 3 – ( 1 )
Aj / Bj = 2 / – 2 = – 1 – ( 2 )
Ak / Bk = –3 / n – ( 3 )
On equating ( 1 ) and ( 2 )
we get
m / 3 = – 1
m = –3
and
on equating ( 2 ) and ( 3 )
we get
–3 / n = – 1
n = – 3 / – 1
n = 3
Therefore (m, n) = ( – 3 , – 3 )
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