Question

if a barabar 3 minus 2 root 2 find the value of a square minus 1/a square​

Answer 1

a=3-2√2

1/a=3+2√2(after rationalization)

(a+1/a)²=a² + 1/a² + 2

(3-2√2+3+2√2)²=a² + 1/a² + 2

(3+3)²-2=a²+1/a²

9²-2=a²+1/a²

:.a²+1/a²=81-2 => 79

PlZ mark me as brainiest answer