If a battery of EMF 6.6V can supply a current of 3A through a resistance of 1.8ohm what current does it supply through another resistance of 2.9 ohm. Also calculate internal resistance of the battery
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Explanation:
Dear Student,
EMF of the cell = 6.6V
Terminal voltage V = ?
Internal resistance of the cell = ?
External load resistance = 1.8 ohm
Load current = 3A
Now, Voltage V = IR = 3*1.8= 5.4 V
Internal resistance r = E- E − VI
6.6 − 5.43= 0.4 ohm.
Also, current through 2.9 ohm,
I = emfR + r = 6.62.9+0.4 = 2 A
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