If a belongs to z I the equation (x-a) (x-10)+1=ohas integral roots then the roots of the equation are
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The given equation is (x−a)(x−10)+1=0
⇒(x−a)(x−10)=−1
∵(x,a)∈Z
Either
x−a=+1 and x−10=−1
⇒x=9 and a=8
Or
(x−a)=−1 and (x−10)=+1
⇒x=11 and a=12
∴(x,a)=(9,8) or (x,a)=(11,12)
⇒a=(8,12)
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