Math, asked by ahmedaadilhabibullah, 3 months ago

3. If the two parallel sides of s trapezium are 16cm and 30cm and perpendicular distance between themis 20cm. Area of trapezium will be



a) 490cm2
b) 510cm2
c) 460cm2
d) 480cm2​

Answers

Answered by Blossomfairy
133

Given :

  • One parallel side of a trapezium = 16 cm
  • Other parallel side of a trapezium = 30 cm
  • Height of a trapezium = 20 cm

To find :

  • Area of trapezium

According to the question,

We know that,

  • Area of trapezium = ½ × (Sum of parallel side) × height

➟ Area of trapezium = ½ × (16 cm + 30 cm) × 20 cm

➟ Area of trapezium = 10 cm × (46 cm)

➟ Area of trapezium = 460 cm²

  • So,the area of trapezium is 460 cm².

Option c) 460 c is correct.

____________________

More formulas :

  • Area of rectangle = Length × Breadth
  • Area of square = Side × Side
  • Surface area of a cube = 6a²
  • Surface area of cuboid = 2(lb + bh + hl)
  • Volume of cuboid = l × b × h
  • Total surface area of a hemisphere = 3πr²
  • Curved surface area of a cone = πrl
  • Total surface area of a cylinder = 2πr(r + h)
  • Perimeter of rectangle = 2 (length + breadth)
Answered by Anonymous
100

\large{\underline{\underline{\textsf{\maltese\: {\red{Given :-}}}}}}

☞ Length of 1st parallel side (a) = 16cm

☞ Length of 2nd parallel side (b) = 30cm

☞ Height (h) of the trapezium = 20cm

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\large{\underline{\underline{\textsf{\maltese\: {\red{To Find :-}}}}}}

☞ Area of trapezium = ?

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\large{\underline{\underline{\textsf{\maltese\: {\red{Diagram :-}}}}}}

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines \qbezier(0,0)(0,0)(3,4)\qbezier(3,4)(3,4)(8,4)\qbezier(8,4)(8,4)(10,0) \qbezier(0,0)(0,0)(10,0)\put(5,4.2){\bf16 cm} \put(5,-.5){\bf30 cm} \qbezier(3,4)(3,4)(3,0)\put(3.2,2){\bf20 cm}\put(4.3,-1.5){\framebox(2.7,.7)} \put(4.3,-1.3){\bf@ BeBrainliest}\end{picture}

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\large{\underline{\underline{\textsf{\maltese\: {\red{Concept Implemented :-}}}}}}

★ Area of trapezium = \dfrac{1}{2} × (Sum of parallel sides) × Height

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\large{\underline{\underline{\textsf{\maltese\: {\red{Solution :-}}}}}}

Area of trapezium = \dfrac{1}{2} ×  (Sum of parallel sides) × Height

☯︎ Putting the values

★ Area of trapezium = \dfrac{1}{2} × (a + b) × h

⇒ Area of trapezium = \dfrac{1}{2} × (16cm + 30cm) × 20cm

⇒ Area of trapezium = \dfrac{1}{2} × 46cm × 20cm

⇒ Area of trapezium = 46cm × 10cm

⇒ Area of trapezium = 460cm²

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Area of trapezium is 460cm².

Option [C] 460 cm² is correct.

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\large{\underline{\underline{\textsf{\maltese\: {\red{Additional Information :-}}}}}}

• A trapezium is a type of quadrilateral whose sum of all angles is 360°.

• One pair of sides are parallel in trapezium.

• Other pair of sides are non parallel.

• There are two types of trapezium :-

(i) Regular Trapezium

(ii) Isosceles Trapezium

• Non parallel sides of isosceles trapezium are equal.

• Diagonals of isosceles  trapezium bisects each other.

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\large{\underline{\underline{\textsf{\maltese\: {\red{Learn more from Brainly :-}}}}}}

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