3. If the two parallel sides of s trapezium are 16cm and 30cm and perpendicular distance between themis 20cm. Area of trapezium will be
a) 490cm2
b) 510cm2
c) 460cm2
d) 480cm2
Answers
Given :
- One parallel side of a trapezium = 16 cm
- Other parallel side of a trapezium = 30 cm
- Height of a trapezium = 20 cm
To find :
- Area of trapezium
According to the question,
We know that,
- Area of trapezium = ½ × (Sum of parallel side) × height
➟ Area of trapezium = ½ × (16 cm + 30 cm) × 20 cm
➟ Area of trapezium = 10 cm × (46 cm)
➟ Area of trapezium = 460 cm²
- So,the area of trapezium is 460 cm².
Option c) 460 cm² is correct.
____________________
More formulas :
- Area of rectangle = Length × Breadth
- Area of square = Side × Side
- Surface area of a cube = 6a²
- Surface area of cuboid = 2(lb + bh + hl)
- Volume of cuboid = l × b × h
- Total surface area of a hemisphere = 3πr²
- Curved surface area of a cone = πrl
- Total surface area of a cylinder = 2πr(r + h)
- Perimeter of rectangle = 2 (length + breadth)
☞ Length of 1st parallel side (a) = 16cm
☞ Length of 2nd parallel side (b) = 30cm
☞ Height (h) of the trapezium = 20cm
☞ Area of trapezium = ?
★ Area of trapezium = × (Sum of parallel sides) × Height
Area of trapezium = × (Sum of parallel sides) × Height
☯︎ Putting the values
★ Area of trapezium = × (a + b) × h
⇒ Area of trapezium = × (16cm + 30cm) × 20cm
⇒ Area of trapezium = × 46cm × 20cm
⇒ Area of trapezium = 46cm × 10cm
⇒ Area of trapezium = 460cm²
∴ Area of trapezium is 460cm².
∴ Option [C] 460 cm² is correct. ✅
• A trapezium is a type of quadrilateral whose sum of all angles is 360°.
• One pair of sides are parallel in trapezium.
• Other pair of sides are non parallel.
• There are two types of trapezium :-
(i) Regular Trapezium
(ii) Isosceles Trapezium
• Non parallel sides of isosceles trapezium are equal.
• Diagonals of isosceles trapezium bisects each other.
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