Question

if a body is projected at an angle of 60° from horizontal then relate the range of projectile with its maximum height​

Answer 1

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Answer 2

Explanation:

Let the velocity of projectile be u.

Angle of projection with the horizontal θ=60

o

So, initial velocity in horizontal direction u

x

=ucosθ=u×cos60

o

=0.5u

Horizontal distance covered in 5 seconds is 90 m

Thus 0.5u=

5

90

⟹ u=36 m/s

Now the body is projected vertically upwards with a speed u=36 m/s

Maximum height reached H=

2g

u

2

=

2×10

36×36

=64.8 m