Question

if a body is projected with a velocity 20root2 m/s making an angle 45with horizontal .then the vertical component of initial velocity is

Answer 1

Answer:

Given:

An object is projected with a velocity of

20√2 m/s at an angle of 45° with the horizontal.

To find :

Vertical component of initial velocity

Concept:

Whenever an object is thrown with these conditions, the object follows oblique projectile trajectory.

Since this is 2D motion, the initial velocity can be divided into 2 components

a) Horizontal component

b) Vertical component

Calculation:

Vertical component of velocity

= v × sin(θ)

= 20√2 × sin(45°)

= 20√2 × (1/√2)

= 20 m/s.