If a body is thrown upward with a velocity of 11.2km/s, what will happen?
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1
Explanation:
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6
Explanation:
19.4km/s
Using energy conservation principle
P.E.
i +K.E =P.E. f +K.E f
where subscripts i and f for initial and final potential and kinetic energy of body
−
r
GGM + 21 m(2v e ) 2 =0+ 21 mv ′ 2
...(i}
v e
= 2GM
R⇒ RGM
= 2v e2
...(ii)
substituting relation in equation (i)
−m 21 v e
2 + 21 m(2v e ) 2 = 2mv 2
Solving for v = 3 v e
=19.4km/s.
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