if a body loses half of its velocity on penetrating 3 cm in a wooden block then how much will it penetrate more before coming to rest
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Answered by
1100
Let the initial velocity of the body be u. Its velocity becomes u/2 after penetrating 3 cm in the block. We can calculate the deceleration of the body using these.
v²= u² +2as
u²/4 = u² + 2a×3
-3u²/4 = 6a
a = -u²/8
Now, we can calculate the distance the body travels till it comes to rest.
v² = u² + 2as
0 = u² +2×(-u²/8)×s
u² = u²s/4
s = 4 cm
Therefore, the body penetrates 1 cm (4-3=1cm) more before coming to rest.
I hope you understand the concept.
All the best!
v²= u² +2as
u²/4 = u² + 2a×3
-3u²/4 = 6a
a = -u²/8
Now, we can calculate the distance the body travels till it comes to rest.
v² = u² + 2as
0 = u² +2×(-u²/8)×s
u² = u²s/4
s = 4 cm
Therefore, the body penetrates 1 cm (4-3=1cm) more before coming to rest.
I hope you understand the concept.
All the best!
Answered by
113
Answer:
Explanation:
Ans : - 4 cm
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