Question

If a body of 5kg is moving in a circle of radius 5 m with a velocity if 100m/s.Then the centripetal force acting on the body is

Answer 1

Answer: 10,000 N (Newton)

Explanation:

Mass (m) = 5 Kg

Velocity (v) = 100 m/s

Radius (r) of path = 5 m

Centripetal Force (F) = mv^2 / r

   = 5 Kg x (100 m/s)^2 / 5 m

   = 100^2 N

   = 10,000 N (Newton)

Thus , this is the answer.

Answer 2

The centripetal force acting on the body is $10^{4} Newton$.

Centripetal Force

• A force applied to an object that keeps it on a circular path and is directed toward the center is known as a centripetal force. CENTRIPETAL FORCE.
• Three factors determine how quickly an item moves along a circular path:

1. Velocity i.e. denoted by ' v '
2. Distance from the path's center i.e. Radius of the circular path, denoted by ' r '
3. Mass i.e. denoted by ' m '

A wonderful illustration : A Merry-Go-Round

Your body attempts to exit the ferris wheel in a straight manner, but you are unable to so. The force you used with your hands to stay on the ride is known as centripetal force.

Now, in the question a body is experiencing a centripetal force $F_{c}$, and given:

Mass of the Body = 5 kg

Velocity of the moving body = $100\ m.s^{-1}$

Radius of the circular path = 5 m

Therefore,

$Centripetal Force\ [F_{c}] = \frac{Mass\ [m]\times Velocity^{2}\ [v^{2}]}{Radius\ [r]}\\ \Rightarrow F_{c} = \frac {m\times v^{2}}{r}\\ \Rightarrow F_{c} = \frac {5\times (100)^{2}}{5} kg.m.s^{-2}\ [Newton]\\ \Rightarrow F_{c} = 10^{4}N$

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