If a body of mass 3 kg is dropped from a tower of the height of 25 m.
Then its kinetic energy at moment the body hits the ground is equal
to;
A. 557 J B. 750 J
C. 1050 J D. 860 J
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6
Answer:
Explanation:
m=3kg velocity ateer 3
h=25m second will be
v= u + gt
=0+10X3=30m/s
K.E= ½ X m X v ²
= ½ X 3 X (30)² = ½ X 3 X 900
= 1350 jule. ans
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