Science, asked by yadav28102004ankit, 8 months ago

If a body of mass 3 kg is dropped from a tower of the height of 25 m.
Then its kinetic energy at moment the body hits the ground is equal
to;
A. 557 J B. 750 J
C. 1050 J D. 860 J

Answers

Answered by Anonymous
6

Answer:

Explanation:

m=3kg                                            velocity ateer 3

h=25m                                            second will be

                                                    v= u + gt

                                                    =0+10X3=30m/s

        K.E= ½ X m X v ²

     = ½  X 3  X (30)²  = ½ X 3 X  900

                                                 = 1350 jule.  ans

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