If a body of mass 3 kg is dropped from the top of a tower of height 25m. Then its kinetic energy after 3 sec is .. don't give any links. pls solve
Answers
The kinetic energy of the body after 3 sec is 1296.54J.
If a body of mass 3 kg is dropeed from the top of a tower of height 25m.
We have to find the kinetic energy after 3 sec.
Kinetic energy is a form of energy of an object which possesses due to its motion. It is the half of the product of mass and square of speed of object. i.e., K.E = 1/2 mv².
- Initial height of the body, h = 25m,
- mass of body , m = 3 kg
- initial velocity of the body, u = 0 m/s
- time, t = 3sec
Using formula, v = u + at
Here, a = g = 9.8 m/s²
⇒ v = 0 + 9.8 × 3 = 29.4 m/s
We know, kinetic energy, K.E = 1/2 mv²
= 1/2 × 3 kg × (29.4 m/s)²
= 1296.54 J
Therefore the kinetic energy of the body after 3 sec is 1296.54J.
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