Question

if a body of mass 40kg is kept at a distance of 0.5m from a body of mass 60kg what is the mutual force of attraction between them​

Answer 1

Answer:

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Answer 2

Answer:

Given -

A body of mass 40 kg is kept at a distance of 0.5m from a body of mass 60 kg

To Find -

Mutual force of attraction between them

Solution -

$f = \frac{gm1 \: m2}{ {d}^{2} }$

$m1 = 40kg \: \: m2 = 60kg \: \: d = 0.5m$

$= > \frac{g \times 40 \times 60}{(0.5)^{2} }$

$= > \frac{g \times 2400}{0.25}$

$= > \frac{6.67 \times {10}^{ - 11} \times 2400}{0.25}$

$= > 64032 \times {10}^{ - 4}$

$= > 6.4032 \times {10}^{ - 7} n$

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