Physics, asked by Nikki57, 1 year ago

If a body of volume V and density d is completely immersed in a liquid of density p then the apparent weight of the body will be

Answers

Answered by TrapNation
56
» Buoyant force acting on the body is
Fb = ( Volume of the displaced liquid)× ( Density of the liquid) × g

= ( Volume of the body) × (rho)×g
= (V)(rho)×g= rhoVg

Weight of the body,
W = ( Density of the body)× ( volume)×g
= (d)(V)(g) = dVg

.°. Apparent weight of the body
w' = w - Fb = dVg - rhoVg
= V(d - rho)g
Answered by QHM
25
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