If a body of volume V and density d is completely immersed in a liquid of density p then the apparent weight of the body will be
Answers
Answered by
56
» Buoyant force acting on the body is
Fb = ( Volume of the displaced liquid)× ( Density of the liquid) × g
= ( Volume of the body) × (rho)×g
= (V)(rho)×g= rhoVg
Weight of the body,
W = ( Density of the body)× ( volume)×g
= (d)(V)(g) = dVg
.°. Apparent weight of the body
w' = w - Fb = dVg - rhoVg
= V(d - rho)g
Fb = ( Volume of the displaced liquid)× ( Density of the liquid) × g
= ( Volume of the body) × (rho)×g
= (V)(rho)×g= rhoVg
Weight of the body,
W = ( Density of the body)× ( volume)×g
= (d)(V)(g) = dVg
.°. Apparent weight of the body
w' = w - Fb = dVg - rhoVg
= V(d - rho)g
Answered by
25
The answer is provided in the attachment.
PLEASE MARK AS BRAINLIEST
PLEASE MARK AS BRAINLIEST
Attachments:
Similar questions