The magnetic field at the centre of a 50 cm long
solenoid is 4.0 x 10-2 T when a current of 8.0 A
flows through it. What is the number of turns in the
solenoid ? Take it π= 3.14.
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jirusharma
sraghavsharma5935
23.09.2019
Physics
Secondary School
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The magnetic field at the centre of a 50cm long solenoid is 4.0 × 10–2 NA–1 m–1 when a current of 8.0A flows through it, calculate the number of turns in the solenoid
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Answer ⇒ The no. of turns is 2000.
Explanation ⇒ Given conditions,
Length = 50 cm.
B = 4.0 × 10⁻² T
Current(i) = 8 A
Using the formula,
B = μ₀N/l × i
∴ 4.0 × 10⁻² = 4π × 10⁻⁷ × N/0.5 × 8
10⁵ × 0.5/8π = N
∴ N = 0.0198 × 10⁵
∴ N = 1.98 × 10³
OR, N ≈ 2000 Turns.
Hope it helps.
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