Physics, asked by Anonymous, 6 months ago

The magnetic field at the centre of a 50 cm long
solenoid is 4.0 x 10-2 T when a current of 8.0 A
flows through it. What is the number of turns in the
solenoid ? Take it π= 3.14.

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jirusharma

sraghavsharma5935

23.09.2019

Physics

Secondary School

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The magnetic field at the centre of a 50cm long solenoid is 4.0 × 10–2 NA–1 m–1 when a current of 8.0A flows through it, calculate the number of turns in the solenoid

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Answer ⇒ The no. of turns is 2000.

Explanation ⇒ Given conditions,

Length = 50 cm.

B = 4.0 × 10⁻² T

Current(i) = 8 A

Using the formula,

B = μ₀N/l × i

∴ 4.0 × 10⁻² = 4π × 10⁻⁷ × N/0.5 × 8

10⁵ × 0.5/8π = N

∴ N = 0.0198 × 10⁵

∴ N = 1.98 × 10³

OR, N ≈ 2000 Turns.

Hope it helps.

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