Question

If a body starts from rest and travels 120cm in the 6th second then what is the acceleration

Answer 1

We know the distance, initial velocity and time, so 
Use the kinematic equation 

y = y₀ +v₀t + ½at² 

because the only unknown is the acceleration. 

The 6th second exists from t = 5 to t = 6 

the distance traveled from rest at t = 5 is 

y₁ = 0 + 0(5) + ½a(5²) 
y₁ = 12.5a 

the distance traveled from rest at t = 6 is 

y₂ = 0 + 0(6) + ½a(6²) 
y₂ = 18a 

we know that y₂ - y₁ = 1.20 m 

18a - 12.5a = 1.20 
5.5a = 1.20 
a = 0.2181818... 
a = 0.218 

Answer 2

Answer:

Step-by-step explanation:

See below