If a body starts from rest and travels 120cm in the 6th second then what is the acceleration
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Answered by
147
We know the distance, initial velocity and time, so
Use the kinematic equation
y = y₀ +v₀t + ½at²
because the only unknown is the acceleration.
The 6th second exists from t = 5 to t = 6
the distance traveled from rest at t = 5 is
y₁ = 0 + 0(5) + ½a(5²)
y₁ = 12.5a
the distance traveled from rest at t = 6 is
y₂ = 0 + 0(6) + ½a(6²)
y₂ = 18a
we know that y₂ - y₁ = 1.20 m
18a - 12.5a = 1.20
5.5a = 1.20
a = 0.2181818...
a = 0.218
Use the kinematic equation
y = y₀ +v₀t + ½at²
because the only unknown is the acceleration.
The 6th second exists from t = 5 to t = 6
the distance traveled from rest at t = 5 is
y₁ = 0 + 0(5) + ½a(5²)
y₁ = 12.5a
the distance traveled from rest at t = 6 is
y₂ = 0 + 0(6) + ½a(6²)
y₂ = 18a
we know that y₂ - y₁ = 1.20 m
18a - 12.5a = 1.20
5.5a = 1.20
a = 0.2181818...
a = 0.218
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114
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