Question

If a body travelling at a velocity of
10m/s changes its velocity to 20m/s
after 20s what will be its accelaration?​

Answer 1

Answer:

The acceleration of the body will be 0.5 m/s².

Explanation:

Given :-

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 20 m/s
• Time taken (t) = 20 s

To find :-

• Acceleration of the body.

Solution :-

Formula used :

${\boxed{\sf{\large{v=u+at}}}}$

Here,

• v = final velocity
• u = initial velocity
• t = time taken
• a = acceleration

[Put values]

→ 20 = 10+a×20

→ 20 = 10+20a

→ 10+20a = 20

→ 20a = 20-10

→ 20a = 10

→ a = 10/20

→ a = 1/2

→ a = 0.5

Therefore, the acceleration of the body is 0.5 m/s².

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★ ${\underline{\underline{\sf{\blue{Some\: formulas:}}}}}$

•$\sf{s=ut+\dfrac{1}{2}at^2}$

•$\sf{v^2=u^2+2as}$

•$\sf{s_n=u+\dfrac{1}{2}a(2n-1)}$

Answer 2

$\tt {\pink{Given}}\begin{cases} \sf{\green{Initial \: Velocity \: (u) = 10 \: m/s}}\\ \sf{\blue{Final \: Velocity \: (v)=20 \: m/s}}\\ \sf{\orange{Time \: taken\:(t)=20 \: seconds}}\\ \sf{\red{Acceleration\:(a)=\:?}}\end{cases}$

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Answer:

$: \implies \sf Acceleration = \dfrac{Change \: in \: velocity}{Time \: taken}$

$:\implies\sf Acceleration = \dfrac{Final \: velocity - Initial \: velocity}{Time \: taken}$

$:\implies\sf Acceleration = \dfrac{20 - 10}{20}$

$:\implies\sf Acceleration = \dfrac{10}{20}$

$: \implies\underline{\boxed{\textsf{ \textbf{Acceleration = 0.5 m/s ^{2} }}}}$

$\therefore\underline{\textsf{ Acceleration produced by the body is \textbf{0.5 m/s ^{2} }}}.$