Question

if a body travels with a velocity 54 km per hour accelerated the rate 5 metre per second square find the distance travelled and 5 seconds​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Distance\:travelled=137.5\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Initial\: velocity(u) = 54 \: km/h \\ \\ \tt : \implies Acceleration(a) = 5 \: m/s^{2}\\ \\ \tt: \implies Time(t) = 5\:sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Distance\:travelled = ?$

• According to given question :

$\tt \circ \: Initial \: velocity = 54 \times \frac{5}{18} = 15 \: m/s \\ \\ \tt \circ \:Acceleration = 5 \: m/s^{2} \\ \\ \tt \circ \: Time = 5 \: sec \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ \tt: \implies s = 15 \times 5 + \frac{1}{2} \times 5 \times {5}^{2} \\ \\ \tt: \implies s =75 + 2.5 \times 25 \\ \\ \tt: \implies s =75 + 62.5 \\ \\ \green{\tt: \implies s =137.5 \: m}$

$\blue{\bold {Some \: related \: formula}} \\ \orange{\tt \circ \: v = u+at} \\ \\ \orange{\tt \circ \: {v}^{2} = {u}^{2} +2as}$