Question

The sum of the digits o a 2 digit number is 11. the number obtained by adding 4 to this number is 41 less than the reversed number
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Answer 1

the number obtained is 38

Answer 2

koLet us take the digit at units place be x.

And the no. at the tens place be y.

ATQ, Sum of digits = x + y = 11.

or y = 11-x. ............(1)

Original number = 10y+x.

Adding 4 to the no. = 10y+x+4.

ATQ, 10y + x + 4 + 41 = 10x + y .

or 10y + x + 45 = 10x + y .

or 10y - y + x - 10x = -45.

or 9y - 9x =-45

or 9(y-x) = 45.

or 9 (11- x - x)=-45.[from ........(1)]

or 9(11-2x) = -45.

or 11-2x = -5.

or- 2x = -5-11

or -2x = -16

or x =(-16/-2)

Therefore x = 8.

y = 11-x = 11-8 = 3.

Original no. =3×10+8 = 30+8 = 38.