If a box contain 5 red balls and 3 blue balls. One ball is drawn at random, the probability of getting a black ball is
1 point
(a) 5/8
(b) 3/8
(c) 1
(d) 0
Answers
Answered by
1
Answer:
0
Step-by-step explanation:
P.E of red ball=5/8
P.E of blue ball=3/8
Since, 1 ball is drawn randomly
P.E of getting black ball =0
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