Question

If a bullet of mass 5 gm moving with velocity 100m/sec penetrates into a wooden block upto 6cm then average force imposed by the bullet on the block is?

Answer 1

Answer:

Given:

Mass = 5 gm

Velocity = 100 m/s

Penetration of 6 cm

To find:

Average force imposed

Concept:

Whenever the bullet is provided with deceleration while penetrating through the block , it experiences a force.

So first Calculate the acceleration by using Equations of Kinematics and finally get force my Multiplying acceleration with mass .

Calculation:

${v}^{2} = {u}^{2} + 2as$

$= > {0}^{2} = {100}^{2} +( 2 \times a \times 0.06)$

$= > a = \dfrac{1000}{(2 \times 0.06)}$

$= > a = 83.33 \: m {s}^{ - 1}$

So average force experienced :

$F = m \times a$

$= > F = \dfrac{5}{1000} \times 83.33$

$= > F = 0.4165 \: N$

So final answer :

$\boxed{ \green{ \huge{ \sf{ \bold{ F = 0.4165 \: N }}}}}$