Question

if a bus travelling at 20 m/s is subjected to steafy deceleration of 5 ms/2 how long will it take to come at rest

Answer 1

U=20m/s

V=0

A=-5m/s2

We know

V=u+at

0=20+(-5)t

-20= -5t

T=4 seconds

Answer 2

u = 20 m/s
a = -5 m/s²
v = 0 m/s
v = u + at
0 = 20 +(-5)t
-20 = -5t
5t = 20
t = 20/5
t = 4 seconds