If a bus travelling at 20m/s is subject to a steady deceleration of 5m/s², how long will it take to come to rest
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Answer:
4 seconds
Explanation:
Initial Velocity = 20 m/s
Final Velocity = 0 m/s (Since bus is coming to rest)
Acceleration = -5 m/s (Since it is decelerating)
Using the first equation of motion, we get:
Equation: v = u + at
Substituting the values,
→ 0 = 20 - 5(t)
→ 5t = 20
→ t = 20/5
→ t = 4 seconds
Hence it would take 4 seconds for the bus to come to rest.
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