If aˣ = c^q = b and c^y = a^z = d ,then
A. xy = qz
B. x/y = q/z
C. x + y = q + z
D. x - y = q - z
Show the necessary calculations
Answers
Answered by
22
using property of logarithm we can solve dis problem easily...
see attachment...
correct option is (A)..
________________________________
.hope it will help u
see attachment...
correct option is (A)..
________________________________
.hope it will help u
Attachments:
Anonymous:
(^_^)
Answered by
27
- a^x=c^q=b,
- c^y=a^z=d
- then
- a=b^1/x and c=b^1/q
- substitute b in places of a and c in second equation
- (b^1/q)^y=(b^1/x)^z=d
- b^y/q = b^z/x
- y/q=z/x
- xy=qz
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