Math, asked by Fuschia, 1 year ago

If aˣ = c^q = b and c^y = a^z = d ,then

A. xy = qz
B. x/y = q/z
C. x + y = q + z
D. x - y = q - z

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Answers

Answered by Anonymous
22
using property of logarithm we can solve dis problem easily...

see attachment...

correct option is (A)..

________________________________
.hope it will help u
Attachments:

Anonymous: (^_^)
Anonymous: thankeww
Anonymous: biloooo
Answered by samyukthay1802
27
  1. a^x=c^q=b,
  2. c^y=a^z=d
  3. then
  4. a=b^1/x and c=b^1/q
  5. substitute b in places of a and c in second equation
  6. (b^1/q)^y=(b^1/x)^z=d
  7. b^y/q = b^z/x
  8. y/q=z/x
  9. xy=qz

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