Question

if a=c^z , b=a^x , c=b^y , then show that xyz=1

Answer 1

a^x=b => x=loga^b
b^y=c=> y=logb^c
c^z=a=> z=logc^a
xyz=(loga^b.logb^c).logc^a
=loga^c.logc^a
=loga^a
=1