if a can do a piece of work in 4 days b can do it in 5 days. with the assistance of c they completed the work in 2 days. find in how many days can c alone do it
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- Given a=1/4 and b=1/5
- with the assistance of c they completed the work in 2 days.hence a+b+c completed work in 2 days
- 2(a+b+c)=1
- on substituting a and b we get 2((1/4)+(1/5)+(1/x))=1
- from this we get x=20 which is c can complete work alone in 20 days
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