If A can do a piece of work
in 4 hours. B andC together 3 hours andA andC together in 2 hours, thenB alone take to do it isIf can do a piece of work in hours. and together hours and and together in hours, then alone take to do it is
Answers
Answered by
2
Answer:
12 hours
A’s one hour’s work = \frac{1}{4}
(B + C)’s one hour’s work = \frac{1}{3}
(A + C)’s one hour’s work = \frac{1}{2}
∴ C’s one hour’s work = \frac{1}{2}-\frac{1}{4} = \frac{2-1}{4} = \frac{1}{4}
B’s one hour’s work = \frac{1}{3}-\frac{1}{4} = \frac{4-3}{12} = \frac{1}{12}
Hence B alone can do the work in 12 hours, so option [D] is correct answer
PLZZ MARK AS BRAINLIEST
Similar questions