If a car accelerated from 5m/sec to 25m/ sec. in 10 seconds, how far will it travel?
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Answered by
49
Answer:
s=150 m..,
Explanation:
given: u=50 m/s .,v=25 ,m/s t=10 sec..,s=? and a=?
form 1st eqn. of motion..,
v=u+a*t
25=5+a*10
i.e a=2 m/s
and now using 2nd eqn. of motion..,
s=ut+1/2*a*t^2
i.e s=5(10)+1/2(2)*(10)^2
s=50+100 m
s= 150 m
samrathag:
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fine...
good but very long
i will solve it without using pen .,but i hv make others understand
Answered by
60
Hey Buddy
Here’s the answer
—————————————————
First , we’ll find acceleration ( a ) with the help of
Initial velocity ( u ) = 5 m/s
Final velocity ( v ) = 25 m/s
Time ( t ) = 10 s
#We know , Change in velocity with respect to time is know as acceleration ,I.e
a = ( v - u )/t
a = ( 25 - 5 )/10
a = 20/10
a = 2 m/s^2
Now using second equation of motion
s = u.t + a.t^2 / 2
Where s is displacement
s = 5 * 10 + 2 * 10 * 10 / 2
s = 50 + 100
s = 150 m
The well travel 150 meter
Hope helped
Peace :)
Here’s the answer
—————————————————
First , we’ll find acceleration ( a ) with the help of
Initial velocity ( u ) = 5 m/s
Final velocity ( v ) = 25 m/s
Time ( t ) = 10 s
#We know , Change in velocity with respect to time is know as acceleration ,I.e
a = ( v - u )/t
a = ( 25 - 5 )/10
a = 20/10
a = 2 m/s^2
Now using second equation of motion
s = u.t + a.t^2 / 2
Where s is displacement
s = 5 * 10 + 2 * 10 * 10 / 2
s = 50 + 100
s = 150 m
The well travel 150 meter
Hope helped
Peace :)
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