Question

If a car at rest accelerate at speed of 144km/hr in 20seconds find distance?

Answer 1

Answer:

s=400m

Explanation:

u=0 SINCE Intially rest

v=u+at

where v=144km\hr=144*5\18 m\s so v=40m\s

40=a*20  so a=2m/s2

s=ut+at^2   u=0

s=1\2*2*20^2

s=400m

hope it helps you

Answer 2

Answer: Distance ,s=400m

Explanation:

From the first law of motion,

V=u+at

144×5/18=20a

10a=20

a=2m/s²

Now from second law of motion,

S=ut+1/2at²

S=1/2×2×20×20

S=20×20

S=400m

Hope it helps you frnd.........