Question

If a car at rest accelerates uniformly and attains a speed of 72 km/hr in 10 s, then it covers a distance of *

Answer 1

Answer:

GIVEN - u = 0

v = 72 km/hr

= 72 ×5/18 = 20 m/s

t = 10 s

then v = u + at

20 = 0 + a×10

20 = 10a

10a = 20

a = 20/10

a = 2 m/s²

v² = u² + 2as

(20)² = (0)²+ 2×2 × s

400 = 4s

s = 400/4

s = 100m

Hope it helps ✌️