If a car at rest accelerates uniformly and attains a speex of 72km/h in 10sec then it covers a distance of
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HERE WE GO ⏬⏬⏬
72 KMPH = 20M/SEC
FROM
v = u +at
20 = 0 + a*10
a = 2 m/s^2
distance = 1/2 a t^2
= 1/2*2*10*10
= 100 m
Hope it will help... ✌❤❤
72 KMPH = 20M/SEC
FROM
v = u +at
20 = 0 + a*10
a = 2 m/s^2
distance = 1/2 a t^2
= 1/2*2*10*10
= 100 m
Hope it will help... ✌❤❤
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