if a car at rest accelerates uniformly to a speed of 144km/h in 20s. find the distance covered? also, the answer is 400m so only reliable answers are needed ;-)
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Chinmay007:
yup I get it! thanks a lot ..
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Initial velocity (u) = 0
Final velocity (v) = 144km/hr = 40m/s
time taken = 20s
So acceleration (a) = 40/20 = 2m/s^2
Using the 3rd equation of motion
v^2 – u^2 = 2as
40^2 – 0 = 2×2×s
1600=4s
s = 1600/4 = 400
So distance travelled is 400m (as stated by you :-P)
HOPE IT HELPS..... :-)
Final velocity (v) = 144km/hr = 40m/s
time taken = 20s
So acceleration (a) = 40/20 = 2m/s^2
Using the 3rd equation of motion
v^2 – u^2 = 2as
40^2 – 0 = 2×2×s
1600=4s
s = 1600/4 = 400
So distance travelled is 400m (as stated by you :-P)
HOPE IT HELPS..... :-)
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hey there! do have a look on my new question!;-)
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