if a car at rest acelarated uniformly to a speed of 144km/hr in 20sec how much will it cover?
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Acceleration of car is
a = (v - u) / t
= [(144 - 0) × 5/18 m/s] / (20 s)
= 40 m/s²
Distance covered = ut + 0.5at²
= 0 + [0.5 × 40 m/s² × (20 s)²]
= 8000 m
= 8 km
Car covers a distance of 8 km
a = (v - u) / t
= [(144 - 0) × 5/18 m/s] / (20 s)
= 40 m/s²
Distance covered = ut + 0.5at²
= 0 + [0.5 × 40 m/s² × (20 s)²]
= 8000 m
= 8 km
Car covers a distance of 8 km
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