If a car covers 2/5th of the total distance with speed v1 and 3/5th distance with speed v2, then average speed for complete motion is?
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ist you need to know avg speed is Total distance/total time In given questions it is mentioned that 2 by 5 of distance is travelled with V1 speed and 3by 5 of distance is travelled with V2 speed You can think it as follow total distance is 5 unit and one travel 2 unit with v1 speed and 3 unit with V2 speed
toatal distance 5 unit total
time= 2/v1+3/v1
avg speed =5/(2/v1 +3/v2)
=5v1 v2/(2v2+3v1)
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