If a car covers 2/5th of the total distance with V1 speed and 3/5th distance with V2,then what is the average speed
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let the total distance be x. time taken to cover 2/5x with speed V1=2/5x/V1 and time taken to cover 3/5x remaining with speed V2=3/5x/V2 . Average speed
= distance travelled/time taken=x/2x/5V1+3x/5V2 =
1/2/5V1 +3/5V2= 5/(2/V1+3/V2) = 5V1V2/2V2+3V1 is the answer .Hope it helps you...
= distance travelled/time taken=x/2x/5V1+3x/5V2 =
1/2/5V1 +3/5V2= 5/(2/V1+3/V2) = 5V1V2/2V2+3V1 is the answer .Hope it helps you...
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