Question

If a car factory checks 320 cars and 12 of them have defects, how many out of 560 will not have defects?

Answer 1

in 320 cars 12 cars have defects means 308 cars does not have defect.

in 560 cars..

320. 308
560. ?


cars does not have defect are...
= [ 560 × 308 ] ÷ 320
= 539

hope it helps you...☺

Answer 2

Answer:

Concept:
Actual experiments and sufficient documentation of the occurrence of occurrences serve as the foundation for experimental probability, sometimes referred to as empirical probability. A number of real experiments are carried out in order to ascertain the likelihood of any event. Random experiments are studies that don't have a predetermined outcome. The results of such experiments are unpredictable. The likelihood of random experiments is calculated repeatedly. A trial is a repeat of an experiment that is performed a certain number of times. The experimental probability's mathematical formula is denoted by;

Probability of an Event P(E) = Number of times an event occurs / Total number of trials.

Step-by-step explanation:

Given:

If a car factory checks 320 cars and 12 of them have defects

Find:

How many out of 560 will not have defects
Solution:

Not defective cars in 320 cars is = 320 - 12 = 308 not defective

Let us assume 'x' be the non-defective cars in 560.

            $\frac{308}{320} = \frac{x}{560}$

           $\frac{320 x}{320} &=\frac{172480}{320}$

           = 539

So the not defective cars will be 539.

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