Question

If a car has a constant acceleration of 4 m/s2, starting from rest, how far has it traveled after 5 seconds?

Answer 1

a = 4 m/s²

u = 0 m/s

t = 5 s

We know, s = ut + ½at²

⟹ s = ½at² = ½(4 m/s²)(5 s)² = (2 m/s²)(25 s²)

⟹ s = 50 m

Answer 2

Given :

• Initial velocity (u) = 0 m/s (as it starts from rest)
• Acceleration (a) = 4 m/s²
• Time (t) = 5 seconds

To find :

• Distance (s)

According to the question,

By Newtons second equation of motion :-

→ s = ut + ½ at²

Where,

• s stands for Distance
• a stands for Acceleration
• t stands for Time
• u stands for Initial velocity

→ Substituting the values,

→ s = 0 × 5 + ½ × 4 × 5 × 5

→ s = 0 + 2 × 25

→ s = 0 + 50

→ s = 50

.°. The distance is 50 m...

_______________________________

More formula :

Newton's first equation of motion :

• v = u + at

Newton's second equation of motion :

• s = ut + ½ at²

Newton's third equation of motion :

• v² = u² + 2as