Question

if a car have running at a speed of 10m/s and acceleration -2m/s^2 and a time of 6 sec find the distance covered by car​

Answer 1

Answer:

u = 10 m/s

t = 6 sec

a = -2 m/s^2

s = ??

s = ut + ½at²

s = 10×6+½ ×2×6×6

s = 60+36

s= 96 m

Answer 2

Answer

Final velocity is zero.and acceleration is −ve

Final velocity is zero.and acceleration is −ve0=u

Final velocity is zero.and acceleration is −ve0=u 2 −2×a×s

Final velocity is zero.and acceleration is −ve0=u 2 −2×a×ss= 2au 2s∝u 2

s∝u 2

s∝u 2 if car moving with a velocity of 10m/s can be stopped by the application of a constant force F in a distance of 20m, since the velocity is tripled stopping distance will become 3 2 =9times..

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