Question

if a car increases it's velocity from 18km/h to 72km/h is 5 seconds calculate​

Answer 1

ANSWER:-

$u = 18 \\ v = 72 \\ t = 5 \\ a = \frac{v - u}{t} \\ = \frac{72 - 18}{5} \\ = \frac{54}{5} = 10.8 \\ \\ s = ut + \frac{1}{2} at \\ = 18 \times 5 + \frac{1}{2} \times 10.8 \times 5 \\ = 90 + \frac{1}{2} \times 54 \\ = 90 + 27 \\ = 117m$

acceleration = 10.8 m/s2

distance= 117m

..........HOPE IT WILL HELP YOU.........

...........THANKS.......