If a car is moving with a speed of 18 km/h suddenly brakes are applied in order to stop the car just before hitting a dog at distance of 300 m. how long will the car take to stop?
Answers
Answered by
1
Explanation:
(v)^²-(u)^²=2as
o-(5/18×18)^²=2as
25=2×a×300
a=300/25
a=1/24ms^²
2.a=v-u/t
1/24=0-5/t
t=1/24×5
=120s
120/60
2 minutes.
ANSWER.
Answered by
0
Answer:
Given, Speed=18km/h,t=5s
a)The speed of the car in m/s=18×
18
5
=5 m/s
b) The retardation is:
a=
t
v−u
=
5
0−5
=1m/s
2
c) The velocity of the as a funcition of time 2sis:
v(t)=5−t⇒v(t)=5−2=3m/s=10.8 km/h
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