Question

If a car is traveling forward at 15 m/s , how fast will it be going at 1.2 seconds if the acceleration is -10 m/s square ?

Answer 1

Answer:

It will be going at 3m/s at 1.2 seconds

Step-by-step explanation:

Let us assume the initial speed of 15m/s as (u).

Let (v) be the speed after some time (t) and (a) be the acceleration.

Now,t=1.2s and a=-10m/s^2

We know,

v=u+at

Hence,v=15+(-10)(1.2)

v=15-12

v=3m/s

Answer 2

Answer:

7.8 m is your answer

Step-by-step explanation:

S=ut+1/2at^2

= 15+1/2*(-10)*(1.2)^2

= 15+1/2*(-10)*(1.44)

= 15+1/2 (-14.4)

= 15+(-7.2)

= 7.8 m