Question

if a car slows down from 27.7m/s to 10.9m/s in 2.37s,what is its acceleration

Answer 1

Given :

• Initial velocity = 27.7 m/s

• Final velocity = 10.9 m/s

• Time = 2.37 s

To Find :

• Acceleration of the car

Solution :

$\large \implies \boxed{\sf a = \dfrac{v - u}{t}}$

ㅤ

$\large \implies\sf a = \dfrac{10.9 - 27.7}{2.37}$

ㅤ

$\large \implies \sf a = \dfrac{ - 16.8}{2.37}$

ㅤ

$\large \implies \sf a = - 7.0 \: m {s}^{ - 2}$

Answer 2

$<b> As we know :- </b>$

acceleration = ( final velocity - initial velocity) / time taken

$<b> a = v - u / t </b>$

= (10.9-27.7) / 2.37

= - 7.088 m/s^2.

$<b> So, its acceleration is -7.088m/s^2. </b>$