Question

If a car start from rest and attained a velocity of 50m/s in 5s. Calculate the acceleration of the car and the distance travelled by a car in 5 sec.

Answer 1

GIVEN:

• Initial Velocity (u) = 0
• Final velocity (v) = 50 m/sec
• Time taken (t) = 5 sec

TO FIND:

• What is the acceleration and distance travelled by the car ?

SOLUTION:

We have given that, a car start from rest and attained a velocity of 50m/s in 5s.

From 1) equation of motion:-

$\large\bf{\star \: v = u + at \: \star}$

According to question:

$\sf{\mapsto 50 = 0 + a \times 5}$

$\sf{\mapsto 50 = 5a}$

$\sf{\mapsto a = \cancel\dfrac{50}{5}}$

$\bf{\mapsto \star \: a = 10 \: m/s^2 \: \star}$

❝ The acceleration of the car is 10 m/s² ❞

Now, we have to find the distance travelled by the car

From 2) equation of motion:-

$\large\bf{\star \: s = ut + \dfrac{1}{2}at^2 \: \star}$

According to question:-

$\sf{\mapsto s = 0\times 5 + \dfrac{1}{\cancel{2}} \times \cancel{10} \times (5)^2 }$

$\sf{\mapsto s = 0 + 5 \times 25 }$

$\sf{\mapsto s = 5 \times 25 }$

$\bf{\mapsto \star \: s = 125 \: m \: \star }$

❝ Hence, the acceleration of the car is 10 m/s² and distance travelled by the car is 125 m ❞

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