if a car travels 50m distance in 4s with acceleration of 5m/s^2 then what was its initial velocity?
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Answered by
2
Hey Mate,
Here Is Your Answer
_________
simple method would be to use S=ut+½at²…second method (but this is some what lengthy)
a=(v-u)/t
5=(v-u)/4
v-u =20…(1)
third equation of motion ,v²=u²+2aS
v²-u²=2aS
(v+u)(v-u)=2*5*50
(v+u)*20=10*50 (using eq 1)
v+u =25…..(2)
subtract eq2-eq1,
v+u-v+u=25–20
2u=5
u=2.5
________
Hope It Helps You.
Here Is Your Answer
_________
simple method would be to use S=ut+½at²…second method (but this is some what lengthy)
a=(v-u)/t
5=(v-u)/4
v-u =20…(1)
third equation of motion ,v²=u²+2aS
v²-u²=2aS
(v+u)(v-u)=2*5*50
(v+u)*20=10*50 (using eq 1)
v+u =25…..(2)
subtract eq2-eq1,
v+u-v+u=25–20
2u=5
u=2.5
________
Hope It Helps You.
Answered by
2
HOPE IT WILL HELP YOU..... ☺☺!!
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