If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20 C, what will be the volume at 50 C?
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For this question we apply Charles' Law:
Charles law states that the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature.
The formula is:
V₁/ T₁ = V₂/T₂
Convert the temperatures to kelvin:
20 C = 293K
50 C = 323K
V₁/ T₁ = V₂/T₂ ------> 0.002m³/ 293 = V₂ / 323
V₂ = 0.002m³/ 293 × 323
= 0.002205m³
The volume of this mercury at 50 C will be 0.002205m³
Charles law states that the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature.
The formula is:
V₁/ T₁ = V₂/T₂
Convert the temperatures to kelvin:
20 C = 293K
50 C = 323K
V₁/ T₁ = V₂/T₂ ------> 0.002m³/ 293 = V₂ / 323
V₂ = 0.002m³/ 293 × 323
= 0.002205m³
The volume of this mercury at 50 C will be 0.002205m³
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