If a certain mass of mercury has a volume of 0.002 m3 at a temperature of 20°C, what will be the volume at 50°C?
A. 0.000010812 m3
B. 0.002010812 m3
C. 0.002021624 m3
D. 0.004021624 m3
Answers
Answer:
Explanation:
Incorrect options..Correct answer: -0.002205m³
For this question we apply Charles' Law:
Charles law states that the volume of a given amount of gas held at constant pressure is directly proportional to the Kelvin temperature.
The formula is:
V₁/ T₁ = V₂/T₂
Convert the temperatures to kelvin:
20 C = 293K
50 C = 323K
V₁/ T₁ = V₂/T₂ ------> 0.002m³/ 293 = V₂ / 323
V₂ = 0.002m³/ 293 × 323
= 0.002205m³
The volume of this mercury at 50 C will be 0.002205m³
Answer:
Right answer: - 0.002205m³ For this inquiry we apply Charles' Law: Charles law expresses that the volume of a given measure of gas held at steady weight is legitimately relative to the Kelvin temperature. The recipe is: V₁/T₁ = V₂/T₂ Convert the temperatures to kelvin: 20 C = 293K 50 C = 323K V₁/T₁ = V₂/T₂ - > 0.002m³/293 = V₂/323 V₂ = 0.002m³/293 × 323 = 0.002205m³ The volume of this mercury at 50 C will be 0.002205m³.