If a certain sum becomes n times in t years formula
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Let Principal = P, Rate = R% per annum, Time = T years and A = Amount due after 3 years
A=P
(1+
R100
)
3
8P=P
(1+
R100
)
3
8=
(1+
R100
)
3
2=1+R100
1=R100
R=100
A=P(1+R100)38P=P(1+R100)38=(1+R100)32=1+R1001=R100R=100
Solution 2 (using formula)
If a certain sum becomes n times in t years, then the rate of compound interest
=
[
n
(1/t)
−1]
×100%=
[
8
(1/3)
−1]
×100%
=(2−1)×100%
=100%
=[n(1/t)−1]×100%=[8(1/3)−1]×100%=(2−1)×100%=100%
A=P
(1+
R100
)
3
8P=P
(1+
R100
)
3
8=
(1+
R100
)
3
2=1+R100
1=R100
R=100
A=P(1+R100)38P=P(1+R100)38=(1+R100)32=1+R1001=R100R=100
Solution 2 (using formula)
If a certain sum becomes n times in t years, then the rate of compound interest
=
[
n
(1/t)
−1]
×100%=
[
8
(1/3)
−1]
×100%
=(2−1)×100%
=100%
=[n(1/t)−1]×100%=[8(1/3)−1]×100%=(2−1)×100%=100%
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