if a charge flown through a cross section of wire in one one direction during 0 to t is given by q= 3 sin (3t) then find out the amount of charge flowing through the wire till t = (pi/6) seconds
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Δq = 3
Explanation:
Given: Charge flown through a cross section of wire in one direction during 0 to t is given by q = 3 sin (3t).
Find: Amount of charge flowing through the wire till t = (π/6) seconds
Solution:
Δq = total charge flown between t = 0 to π/6
= 3 |sin3t| .... t ranges from 0 to π/6
= 3 [sin π/2]
= 3 [1] as Sin π/2 is sin 90 which is one.
Δq = 3
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