Question

if a circle touches all the four sides of a quadrilateral ABCD at points P,Q,R,S then show that AB+CD=BC+AD.​

Answer 1

Answer:

Step-by-step explanation:

To Prove  :  AB + CD = BC + AD

Proof :

As the circle touches all four sides of the quadrilateral,

AB = BC = CD = DA = diameter of the circle.

∴ AB + CD = BC + AD

Hence proved